Jeopardy gets slope degree/percent wrong

I recall discussions here long ago about the difference between slope angle measurements in degrees and percent. Tonight on Jeopardy in the combination of a clue and correct response, they said Talladega race course turns are banked at a maximum of 33 percent. According to NASCAR, the steeper curves are banked at 33 degrees, or about 65 percent.

On Tuesday, July 5, 2016 at 12:52:52 AM UTC-6, Richard Henry wrote:
I recall discussions here long ago about the difference between slope angle measurements in degrees and percent. Tonight on Jeopardy in the combination of a clue and correct response, they said Talladega race course turns are banked at a maximum of 33 percent. According to NASCAR, the steeper curves are banked at 33 degrees, or about 65 percent.

I remember the original topic. If I remember correctly it had more to do with blowhards than anything else. But this is RSA so.........oh well.

But what is 100%? Is a horizontal line 0 and the vertical of a 90 deg. 100%? "per cent" of what? 360? Never gave it much though. I remember a section of "the peak" at Park City that was supposed to be 54 deg.(?). It seemed straight down.

On Tuesday, July 5, 2016 at 5:56:39 AM UTC-7, pigo wrote:
On Tuesday, July 5, 2016 at 12:52:52 AM UTC-6, Richard Henry wrote:
I recall discussions here long ago about the difference between slope angle measurements in degrees and percent. Tonight on Jeopardy in the combination of a clue and correct response, they said Talladega race course turns are banked at a maximum of 33 percent. According to NASCAR, the steeper curves are banked at 33 degrees, or about 65 percent.

I remember the original topic. If I remember correctly it had more to do with blowhards than anything else. But this is RSA so.........oh well.

But what is 100%? Is a horizontal line 0 and the vertical of a 90 deg. 100%? "per cent" of what? 360? Never gave it much though. I remember a section of "the peak" at Park City that was supposed to be 54 deg.(?). It seemed straight down.

It is 100% when the amount of rise (or fall, in the case of skiing) is the same as the amount moved forward. The angle where that happens is 45 degrees. There are very few ski slopes that approach that steepness because snow generally won't stay on it.

The mathematical formula is 100 * tan(angle) -- the tangent of the angle multiplied by 100 to convert to percent.

On 07/05/2016 08:18 AM, Richard Henry wrote:
On Tuesday, July 5, 2016 at 5:56:39 AM UTC-7, pigo wrote:
On Tuesday, July 5, 2016 at 12:52:52 AM UTC-6, Richard Henry
wrote:
I recall discussions here long ago about the difference between
slope angle measurements in degrees and percent. Tonight on
Jeopardy in the combination of a clue and correct response, they
said Talladega race course turns are banked at a maximum of 33
percent. According to NASCAR, the steeper curves are banked at
33 degrees, or about 65 percent.

I remember the original topic. If I remember correctly it had more
to do with blowhards than anything else. But this is RSA
so.........oh well.

But what is 100%? Is a horizontal line 0 and the vertical of a 90
deg. 100%? "per cent" of what? 360? Never gave it much though. I
remember a section of "the peak" at Park City that was supposed to
be 54 deg.(?). It seemed straight down.

It is 100% when the amount of rise (or fall, in the case of skiing)
is the same as the amount moved forward. The angle where that happens
is 45 degrees. There are very few ski slopes that approach that
steepness because snow generally won't stay on it.

The mathematical formula is 100 * tan(angle) -- the tangent of the
angle multiplied by 100 to convert to percent.

Or, for the mathematically-challenged, multiply or divide by 2.

--
Cheers, Bev
---------------------------------------------------------------
"Advertising is the rattling of a stick inside a swill bucket."
-- George Orwell

On Tuesday, 5 July 2016 09:57:33 UTC-7, The Real Bev wrote:

Or, for the mathematically-challenged, multiply or divide by 2.

--
Cheers, Bev

Huh??? 45 degres = 100 % hows that a multiply/divide by 2?

http://www.greenbeltconsulting.com/a...tionships.html

On Tuesday, July 5, 2016 at 11:56:14 AM UTC-7, wrote:
On Tuesday, 5 July 2016 09:57:33 UTC-7, The Real Bev wrote:

Or, for the mathematically-challenged, multiply or divide by 2.

--
Cheers, Bev

Huh??? 45 degres = 100 % hows that a multiply/divide by 2?

http://www.greenbeltconsulting.com/a...tionships.html

That's all the math some people can handle.

On Tuesday, July 5, 2016 at 9:18:32 AM UTC-6, Richard Henry wrote:
On Tuesday, July 5, 2016 at 5:56:39 AM UTC-7, pigo wrote:
On Tuesday, July 5, 2016 at 12:52:52 AM UTC-6, Richard Henry wrote:
I recall discussions here long ago about the difference between slope angle measurements in degrees and percent. Tonight on Jeopardy in the combination of a clue and correct response, they said Talladega race course turns are banked at a maximum of 33 percent. According to NASCAR, the steeper curves are banked at 33 degrees, or about 65 percent.

I remember the original topic. If I remember correctly it had more to do with blowhards than anything else. But this is RSA so.........oh well.

But what is 100%? Is a horizontal line 0 and the vertical of a 90 deg. 100%? "per cent" of what? 360? Never gave it much though. I remember a section of "the peak" at Park City that was supposed to be 54 deg.(?). It seemed straight down.

It is 100% when the amount of rise (or fall, in the case of skiing) is the same as the amount moved forward. The angle where that happens is 45 degrees. There are very few ski slopes that approach that steepness because snow generally won't stay on it.

The mathematical formula is 100 * tan(angle) -- the tangent of the angle multiplied by 100 to convert to percent.

In my world that's a 12/12 pitched roof. Anything over an 8 needed to have stickers nailed down to walk on without sliding off. And 8 was scary. Kinda depended on the distance from the edge of the roof to the ground.

I think that the rock structure and wind were enough to hold the snow on 51/50. I don't think I ever skied it when it was not unbreakable windblown. *Soft* but you weren't going to break through it.

On 07/06/2016 07:16 AM, pigo wrote:
On Tuesday, July 5, 2016 at 9:18:32 AM UTC-6, Richard Henry wrote:

The mathematical formula is 100 * tan(angle) -- the tangent of the
angle multiplied by 100 to convert to percent.

In my world that's a 12/12 pitched roof. Anything over an 8 needed to
have stickers nailed down to walk on without sliding off. And 8 was
scary. Kinda depended on the distance from the edge of the roof to
the ground.

BIL was a roofer in New York. He told us about "chicken ladders".

--
Cheers, Bev
"Mr Panetta also revealed that the US Navy Seals made the final
decision to kill bin Laden rather than the president."
--S. Swinford, The Telegraph
[Aside from that minor error, those Seals did a fantastic job!] --Bev

On Wednesday, July 6, 2016 at 9:21:11 AM UTC-6, The Real Bev wrote:

BIL was a roofer in New York. He told us about "chicken ladders".

8/12 were the worst. Because you *can* walk on them. If all is dry, free of sawdust, and debris, you can get around. But it's really easy to go off. Sorta like when something weighs a few hundred pounds you think you can get it up there so you try. Best if the beam weighs 40,000 lbs so you just order the crane.